Question

The distance of point of intersection of lines = $\frac { y + 3 } { - 4 }$

= and = = from (1, –4, 7)

• A. 6
• B. $\sqrt { 24 }$
• C. $\sqrt { 26 }$
• D. None of these

Answer 1

Answer: (C)

$\sqrt { 26 }$

Answer 2

4 + l₁ = 1 + 2l₂ ̃ l₁ –2l₂ = –3 ... (1)

– 3 –4l₁ = –1 –3l₂ ̃ 4l₁ –3l₂ = –2 ... (2)

From (1) and (2),–5 × 2 = –10

l₂ = 2, l₁ = 1

̃ point of intersection (4 + 1, –3 –4, –1 + 7)

i.e. (5, –7, 6)

Distance of (5, –7, 6) from (1, –4, 7)

= $\sqrt { 16 + 9 + 1 }$= $\sqrt { 26 }$