Question

The distance of point (1, –2, 3) from the plane x – y + z – 5= 0 measured parallel to = = $\frac { z - 1 } { - 6 }$ is –

• A. 1
• B. 2
• C. 0
• D. –3

Answer 1

Answer: (A)

1

Answer 2

A point on the line || to given line & passing through given point is (2r + 1, 3r – 2, – 6r + 3).

This point lies on the plane for r = $\frac { 1 } { 7 }$ ,

so the desired distance = 1.