Question
Question: The distance of a galaxy is \(56\times {{10}^{25}}m\) . Assume the speed of light to be \(3\times {{...
The distance of a galaxy is 56×1025m . Assume the speed of light to be 3×108ms−1 . Find the time taken by light to travel this distance.
a)0.87×1018s
b)1.87×1018s
c)18.7×1018s
d)1.87×1017s
Solution
In the question the distance from a particular galaxy is given as 56×1025m . The light travels with a constant speed in a medium and for every medium it is a constant. Hence using the relation between the speed and the distance covered by the object, the time taken can be determined accordingly.
Formula used:
s=td
Complete answer:
Let us say a particle travels with a constant speed ‘s’ in a particular medium. If the particle covers a distance ‘d’ in time ‘t’, than the relation between the above parameters of motion is given by the equation,
s=td
Light exhibits a dual nature i.e. it can be treated to be a wave as well at the same time it can be treated as a particle. For the above problems let us consider the light to be consisting of particles called photons. Let us say a photon leaves the galaxy and travels with a speed of 3×108ms−1. The distance from the galaxy is given as 56×1025m . hence using the above relation the time taken by the photon to reach Earth or a reference point is equal to,
s=td⇒3×108ms−1=t56×1025m⇒t=3×108ms−156×1025m∴t=1.87×1018s
Therefore the correct answer of the above question is option b.
Note:
Between the galaxy and the Earth there is nothing but outer space. Outer space is perfectly not vacuum, but it can always be treated equivalent to a vacuum. Light travels with a maximum speed in vacuum as the refractive index of vacuum is one. As the refractive index of a medium increases i.e. mediums that are optically denser, light travels with least speed in such mediums.