The distance from the pointegral (2, 2, 2) to the plane 2x-y... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The distance from the point (2, 2, 2) to the plane 2x-y+3z = 5 is equal to

A

$\frac{3\sqrt{7}}{2}$

B

$\frac{\sqrt{3}}{2}$

C

$\frac{3\sqrt{14}}{7}$

D

$\frac{3\sqrt{14}}{14}$

E

$\frac{\sqrt{3}}{3}$

Answer

$\frac{3\sqrt{14}}{14}$

Explanation

Solution

The correct option is (D) : $\frac{3\sqrt{14}}{14}$