The distance between the two planes 2x + 3y + 4z = 4 and 4x... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The distance between the two planes 2x + 3y + 4z = 4 and 4x + 6y +8z = 12 is

A

2 units

B

8 units

C

$\frac{2}{\sqrt {29}}$ units

D

4 units

Answer

$\frac{2}{\sqrt {29}}$ units

Explanation

Solution

The correct answer is Option (C) : $\frac{2}{\sqrt {29}}$ units