Question

The distance between the two charges $25\mu C$ and $36\mu C$ is $11cm$ At what point on the line joining the two, the intensity will be zero

• A. At a distance of $5cm$from $25\mu C$
• B. At a distance of $5cm$from $36\mu C$
• C. At a distance of $10cm$from $25\mu C$
• D. At a distance of $11cm$from $36\mu C$

Answer 1

Answer: (A)

At a distance of $5cm$from $25\mu C$

Answer 2

Suppose electric field is zero at point N in the figure then

At N |E₁| = |E₂|

which gives $x_{1} = \frac{x}{\sqrt{\frac{Q_{2}}{Q_{1}}} + 1} = \frac{11}{\sqrt{\frac{36}{25}} + 1} = 5cm$