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Question

Mathematics Question on Coordinate Geometry

The distance between the points (2,3)(2, -3) and (2,3)(-2, 3) is:

A

2132\sqrt{13} units

B

55 units

C

13213\sqrt{2} units

D

1010 units

Answer

2132\sqrt{13} units

Explanation

Solution

The distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substituting the given points (x1,y1)=(2,3)(x_1, y_1) = (2, -3) and (x2,y2)=(2,3)(x_2, y_2) = (-2, 3):

d=(22)2+(3(3))2d = \sqrt{(-2 - 2)^2 + (3 - (-3))^2}

d=(4)2+(6)2=16+36=52=213d = \sqrt{(-4)^2 + (6)^2} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13}

Thus, the distance is 5 units.