Question

The distance between the plates of a parallel plate condenser is 60 volts. If the distance between the plates is increased to, then

• A. The potential difference of the condenser will become 180 volts
• B. The P.D. will become 20 volts
• C. The P.D. will remain unchanged
• D. The charge on condenser will reduce to one third

Answer 1

Answer: (A)

The potential difference of the condenser will become 180 volts

Answer 2

For capacitor$\frac { V _ { 1 } } { V _ { 2 } } = \frac { d _ { 1 } } { d _ { 2 } }$

⇒$V _ { 2 } = \frac { V _ { 1 } \times d _ { 2 } } { d _ { 1 } } = \frac { 60 \times 12 } { 4 } = 180 \mathrm {~V}$