Question
Question: The distance between the parallel lines given by the equations, \[\overrightarrow{r}.(2\widehat{i}-2...
The distance between the parallel lines given by the equations, r.(2i−2j+k)+3=0 and r.(4i−4j+2k)+5=0 is
A. 21
B. 61
C. 32
D. 1
Solution
Hint: the distance between two parallel lines r.(ai+bj+ck)+c1=0 and r.(ai+bj+ck)+c2=0 is given by a2+b2+c2c1−c2. multiply the line equation (1) with 2 to get both as parallel as parallel lines and then apply the distance between two parallel lines formulas.
Complete step-by-step solution -
Given the line equations are r.(2i−2j+k)+3=0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . .(1)
r.(4i−4j+2k)+5=0. . . . . . . . . . . . . . . . . . . . . . . . . . . . .(2)
Multiply the equation (1) with 2 then we will get
r.(4i−4j+2k)=−6. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (3)
Rewriting equation (2) as same
r.(4i−4j+2k)=−5. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (4)
We know that the distance between two parallel lines is given by a2+b2+c2c1−c2
=42+42+22−6−(−5)
=16+16+4−1
=61
So, the distance between the parallel lines given by equations r.(2i−2j+k)+3=0 and r.(4i−4j+2k)+5=0 is 61
So, the correct option is option (B)
Note: In geometry, the parallel lines are lines which do not intersect at any point in a plane. Skew lines and parallel lines are different; note that skew lines never meet and they are not parallel. The parallel lines equation differ only in constant value and values of a, b, c that is the coefficient of x, y, z of two parallel lines are same