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Question: The distance between the parallel lines given by the equations, \[\overrightarrow{r}.(2\widehat{i}-2...

The distance between the parallel lines given by the equations, r.(2i^2j^+k^)+3=0\overrightarrow{r}.(2\widehat{i}-2\widehat{j}+\widehat{k})+3=0 and r.(4i^4j^+2k^)+5=0\overrightarrow{r}.(4\widehat{i}-4\widehat{j}+2\widehat{k})+5=0 is
A. 12\dfrac{1}{2}
B. 16\dfrac{1}{6}
C. 23\dfrac{\sqrt{2}}{3}
D. 11

Explanation

Solution

Hint: the distance between two parallel lines r.(ai^+bj^+ck^)+c1=0\overrightarrow{r}.(a\widehat{i}+b\widehat{j}+c\widehat{k})+{{c}_{1}}=0 and r.(ai^+bj^+ck^)+c2=0\overrightarrow{r}.(a\widehat{i}+b\widehat{j}+c\widehat{k})+{{c}_{2}}=0 is given by c1c2a2+b2+c2\left| \dfrac{{{c}_{1}}-{{c}_{2}}}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}} \right|. multiply the line equation (1) with 2 to get both as parallel as parallel lines and then apply the distance between two parallel lines formulas.

Complete step-by-step solution -
Given the line equations are r.(2i^2j^+k^)+3=0\overrightarrow{r}.(2\widehat{i}-2\widehat{j}+\widehat{k})+3=0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . .(1)
r.(4i^4j^+2k^)+5=0\overrightarrow{r}.(4\widehat{i}-4\widehat{j}+2\widehat{k})+5=0. . . . . . . . . . . . . . . . . . . . . . . . . . . . .(2)
Multiply the equation (1) with 2 then we will get
r.(4i^4j^+2k^)=6\overrightarrow{r}.(4\widehat{i}-4\widehat{j}+2\widehat{k})=-6. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (3)
Rewriting equation (2) as same
r.(4i^4j^+2k^)=5\overrightarrow{r}.(4\widehat{i}-4\widehat{j}+2\widehat{k})=-5. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (4)
We know that the distance between two parallel lines is given by c1c2a2+b2+c2\left| \dfrac{{{c}_{1}}-{{c}_{2}}}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}} \right|
=6(5)42+42+22=\left| \dfrac{-6-(-5)}{\sqrt{{{4}^{2}}+{{4}^{2}}+{{2}^{2}}}} \right|
=116+16+4=\left| \dfrac{-1}{\sqrt{16+16+4}} \right|
=16=\dfrac{1}{6}
So, the distance between the parallel lines given by equations r.(2i^2j^+k^)+3=0\overrightarrow{r}.(2\widehat{i}-2\widehat{j}+\widehat{k})+3=0 and r.(4i^4j^+2k^)+5=0\overrightarrow{r}.(4\widehat{i}-4\widehat{j}+2\widehat{k})+5=0 is 16\dfrac{1}{6}
So, the correct option is option (B)

Note: In geometry, the parallel lines are lines which do not intersect at any point in a plane. Skew lines and parallel lines are different; note that skew lines never meet and they are not parallel. The parallel lines equation differ only in constant value and values of a, b, c that is the coefficient of x, y, z of two parallel lines are same