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Question

Physics Question on Electromagnetic induction

The distance between the ends of wings of an aeroplane is 5m5\, m. The aeroplane is moving with velocity of 200km/sec200\, km/sec in a magnetic field of 10T.10\, T. The emf induced across the ends of wings will be:

A

10710^{7} volt

B

1010 volt

C

10610^{6} volt

D

none of these

Answer

10710^{7} volt

Explanation

Solution

e=Bvl...(i)e=B v l\,\,\,\,...(i) Here :B=10T,v=200km/sec: B=10\, T , v=200 \,km / sec =2×105m/sec,l=5m=2 \times 10^{5}\, m / sec , l=5\, m Putting given values is eq (i) e=10×2×105×5\therefore e =10 \times 2 \times 10^{5} \times 5 =1×107=1 \times 10^{7} volt