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Question: The distance between the body centred atom and a corner atom in sodium (a = 4.225 Å) is....

The distance between the body centred atom and a corner atom in sodium (a = 4.225 Å) is.

A

3.66 Å

B

3.17 Å

C

2.99 Å

D

2.54 Å

Answer

3.66 Å

Explanation

Solution

Sodium has bcc structure.

The distance between body centre and a corner =3a2= \frac{\sqrt{3}a}{2}

=3×4.2252=3.66A˚= \frac{\sqrt{3} \times 4.225}{2} = 3.66Å