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Question: The distance between \(H^{+}\) and \(Cl^{-}\) ions in HCl molecule is 1.28 Å. What will be the poten...

The distance between H+H^{+} and Cl−Cl^{-} ions in HCl molecule is 1.28 Å. What will be the potential due to this dipole at a distance of 12 Å on the axis of dipole

A

0.13 V

B

1.3 V

C

13 V

D

130 V

Answer

0.13 V

Explanation

Solution

V=9×109.pr2V = 9 \times 10^{9}.\frac{p}{r^{2}}

=9×109×(1.6×10−19)×1.28×10−10(12×10−10)2= 9 \times 10^{9} \times \frac{(1.6 \times 10^{- 19}) \times 1.28 \times 10^{- 10}}{(12 \times 10^{- 10})^{2}}= 0.13V