Question

The distance between an object and a divergent lens is $m$ times the focal length of the lens. The linear magnification produced by the lens is

• A. $m$
• B. $\frac{1}{m}$
• C. $m+1$
• D. $\frac{1}{m+1}$

Answer 1

Answer: (D)

$\frac{1}{m+1}$

Answer 2

Given, $u=-m f$
$\therefore \frac{1}{v}-\frac{1}{(-m f)}=-\frac{1}{f}$
$\Rightarrow \frac{1}{v}=-\frac{1}{f}\left(1+\frac{1}{m}\right)$
$\Rightarrow -\frac{v}{f}=\frac{m}{m+1}$
$\Rightarrow - \frac{v}{u}=\left(\frac{1}{1+m}\right)$