Question

The distance advanced by screw of a screw gauge is 2mm in four rotation. Its cap is divided into 50 division. There is no zero error. If the screw reads 3 divisions on the main scale and 32 divisions on the cap, then the diameter of the wire is -

• A. 3.32 mm
• B. 1.82 mm
• C. 2.82 mm
• D. 4.7 mm

Answer 1

Answer: (B)

1.82 mm

Answer 2

pitch = 2/4

LC = $\frac { 2 / 4 } { 50 }$ = .01 mm

diameter = 3 × 0.5 + 32 × .01

= 1.5 + .32

= 1.82 mm