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Question: The dissolution of Al(OH)<sub>3</sub> by a solution of NaOH results in the formation of :...

The dissolution of Al(OH)3 by a solution of NaOH results in the formation of :

A

[Al (H2O)4(OH)2]+

B

[Al (H2O)3(OH)3]

C

[Al (H2O)2(OH)4]

D

[Al (H2O)6(OH)3]

Answer

Al(H<sub>2</sub>O)<sub>2</sub>(OH)<sub>4</sub>Al (H<sub>2</sub>O)<sub>2</sub>(OH)<sub>4</sub>

Explanation

Solution

Al(OH)3 dissolve in NaOH solution to give Al(OH)4 ion which is supposed to have the octahedral complex species [Al(OH)4(H2O)2] in aqueous solution

Al(OH)3 + NaOH(aq) ® [Al (OH)4(H2O)2](aq) + Na+(aq)