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Chemistry Question on Acids and Bases

The dissociation constants of two acids HA1HA_1 and HA2HA_2 are 3.0 × 10−43.0\, \times \, 10^{-4} and 1.8 × 10−51.8\, \times \,10^{-5} respectively.The relative strengths of the acids will be

A

1:04

B

4:01

C

1:16

D

16:01

Answer

4:01

Explanation

Solution

Strength of acidHA1Strength of acidHA2=K1K2\frac{\text{Strength of acid} HA_{1}}{\text{Strength of acid} HA_{2}}=\sqrt{\frac{K_{1}}{K_{2}}} =3.0×10−41.8×10−5=41=\sqrt{\frac{3.0\times10^{-4}}{1.8\times10^{-5}}}=\frac{4}{1}