Question

The displacement x (in metres) of a particle performing simple harmonic motion is related to time t (in seconds) as x = 0.05 cos$\left( 4\pi t + \frac{\pi}{4} \right)$. The frequency of the motion will be

• A. 0.5 Hz
• B. 1.0 Hz
• C. 1.5 Hz
• D. 2.0 Hz

Answer 1

Answer: (D)

2.0 Hz

Answer 2

From the given equation, coefficient of t = $\omega = 4\pi$

$\therefore$ n = $\frac{\omega}{2\pi} = \frac{4\pi}{2\pi} = 2$Hz