Question: The displacement x (in metres) of a particle performing simple harmonic motion is related to time t ...

Question

The displacement x (in metres) of a particle performing simple harmonic motion is related to time t (in seconds) as $x = 0.05\cos\left( 4\pi t + \frac{\pi}{4} \right)$ . The frequency of the motion will be

Answer 1

Solution

From the given equitation

$\omega = 2\pi n = 4\pi$ ⇒ $n = 2Hz$