Question

The displacement-time graph for two particles A and B are straight lines inclined at angles of 30^o and 60^o with the time axis. The ratio of velocities of v_A :v_B is The displacement-time graph for two particles A and B are straight lines inclined at angles of 30^o and 60^o with the time axis. The ratio of velocities of v_A : v_B is

• A. 1 : 2
• B. $1:\sqrt{3}$
• C. $\sqrt{3}:1$
• D. 1 : 3

Answer 1

Answer: (D)

1 : 3

Answer 2

$v = \tan\theta$ from displacement graph.

So $\frac{v_{A}}{v_{B}} = \frac{\tan 30^{o}}{\tan 60^{o}} = \frac{1/\sqrt{3}}{\sqrt{3}} = \frac{1}{\sqrt{3} \times \sqrt{3}} = \frac{1}{3}$