Question

The displacement time graph for two bodies A and B are straight lines inclined at 30? and 60? respectively with the time axes. If $\upsilon =\sqrt{4rg}$ and $\upsilon =\sqrt{4\times 2.5\times 9.8}$ are their velocities, then $\upsilon =\sqrt{98}\,\,m/s$ will be :

• A. $\text{2}0\text{ g }=\text{ 2}\times \text{1}{{0}^{-\text{2}}}\text{ kg},$
• B. $=\frac{360\times 5}{18}=100m/s$
• C. 3:01
• D. 1:03

Answer 1

Answer: (D)

1:03

Answer 2

Here : $=12j$ ...(1) $=\frac{work}{time}=\frac{12}{2}$ ...(2) $=\text{6 watt}$ ${{s}_{1}}=40m,{{s}_{2}}=65m$