Question: The displacement of the particle is given by $y = a + bt + ct^{2} - dt^{4}.$ The initial velocity...

Question

The displacement of the particle is given by

$y = a + bt + ct^{2} - dt^{4}.$ The initial velocity and acceleration are respectively

Answer 1

Given $y = a + bt + ct^{2} - dt^{4}$

∴ v = $\frac{\mathbf{dy}}{\mathbf{dt}}\mathbf{= 0 + b + 2ct}\mathbf{-}\mathbf{4d}\mathbf{t}^{\mathbf{3}}$

Putting $t = 0,$ v_initial = b

So initial velocity = b

Now, acceleration (1) $= \frac{dv}{dt} = 0 + 2c - 12dt^{2}$

Putting t = 0, a_initial = 2c

Question: The displacement of the particle is given by \(y = a + bt + ct^{2} - dt^{4}.\) The initial velocity...