Question

The displacement of an oscillating particle varies with time (in seconds) according to the equation. The maximum acceleration of the particle approximately

• A. 5.21 cm/sec²
• B. 3.62 cm/sec²
• C. 1.81 cm/sec²
• D. 0.62 cm/sec²

Answer 1

Answer: (D)

0.62 cm/sec²

Answer 2

By comparing the given equation with standard equation, $y = a \sin ( \omega t + \phi )$

We find that $a = 1$and $\omega = \pi / 4$

Now maximum acceleration $= \omega ^ { 2 } a$

$= \left( \frac { \pi ^ { 2 } } { 4 } \right) = \left( \frac { 3.14 } { 4 } \right) ^ { 2 } = 0.62 \mathrm {~cm} / \mathrm { sec } ^ { 2 }$