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Question: The displacement of a particle varies according to the relation x = 4(cosπt + sinπt). The amplitude ...

The displacement of a particle varies according to the relation x = 4(cosπt + sinπt). The amplitude of the particle is

A

8

B

– 4

C

4

D

424\sqrt{2}

Answer

424\sqrt{2}

Explanation

Solution

For given relation

Resultant amplitude =42+42=42= \sqrt{4^{2} + 4^{2}} = 4\sqrt{2}