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Question: The displacement of a particle, moving in a straight line, is given by \(s = 2t^{2} + 2t + 4\) where...

The displacement of a particle, moving in a straight line, is given by s=2t2+2t+4s = 2t^{2} + 2t + 4 where ss is in metres and tt in seconds. The acceleration of the particle is

A

2 m/s2

B

4 m/s2

C

6 m/s2

D

8 m/s2

Answer

4 m/s2

Explanation

Solution

Given s=2t2+2t+4s = 2t^{2} + 2t + 4 ∴ velocity (v) =dsdt=4t+2= \frac{ds}{dt} = 4t + 2 and acceleration (1) =dvdt=4(1)+0=4m/s2= \frac{dv}{dt} = 4(1) + 0 = 4m/s^{2}