Question: The displacement of a particle is given by $y = a + bt + ct^{2} - dt^{4}$. The initial velocity a...

Question

The displacement of a particle is given by

$y = a + bt + ct^{2} - dt^{4}$ . The initial velocity and acceleration are respectively

Answer 1

$y = a + bt + ct^{2} - dt^{4}$

$\therefore\mspace{6mu} v = \frac{dy}{dt} = b + 2ct - 4dt^{3}$ and $a = \frac{dv}{dt} = 2c - 12dt^{2}$

Hence, at t = 0, v_initial = b and a_initial = 2c.

Question: The displacement of a particle is given by \(y = a + bt + ct^{2} - dt^{4}\). The initial velocity a...