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Physics Question on distance and displacement

The displacement of a particle executing simple harmonic motion is given by y=A0+Asinωt+Bcosωt.y=A_0+A sin\omega t+Bcos\omega t. Then the amplitude of its oscillation is given by:

A

A0+A2+B2A_0+\sqrt {A^2+B^2}

B

A2+B2\sqrt {A^2+B^2}

C

A02+(A2+B2)\sqrt {A_0^2+(A^2+B^2})

D

A+BA+B

Answer

A2+B2\sqrt {A^2+B^2}

Explanation

Solution

The correct option is (B) :A2+B2\sqrt {A^2+B^2}