Question
Physics Question on Electric Field
The displacement of a charge Q in the electric field E=e11+e2j+e3k is r=ai+bj. The work done is
A
Q(ae1+be2)
B
Qae12+be22
C
Q(e1+e2)a2+b2
D
Qe12+e22a+b
Answer
Q(ae1+be2)
Explanation
Solution
By using W=Q(EΔr)
⇒W=Q[(e1l+e2j+e3k)⋅(ai+bj)]
=Q(e1a+e2b)