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Question

Physics Question on Electric Field

The displacement of a charge QQ in the electric field E=e11+e2j+e3kE=e_{1} 1+e_{2} j+e_{3} k is r=ai+bjr=a i+b j. The work done is

A

Q(ae1+be2)Q (ae_1 + be_2)

B

Qae12+be22Q \, \overline {{ae_1 } ^2 + {be_2 }^2}

C

Q(e1+e2)a2+b2Q(e_1 + e_2)\,\, \overline{a^2 + b^2}

D

Qe12+e22a+bQ \overline{e_1^2 + e_2^2} \,\,a + b

Answer

Q(ae1+be2)Q (ae_1 + be_2)

Explanation

Solution

By using W=Q(EΔr)W = Q ( E \Delta r )
W=Q[(e1l+e2j+e3k)(ai+bj)]\Rightarrow W=Q\left[\left(e_{1}\, l+e_{2}\, j+e 3 \,k\right) \cdot(a i+b j)\right]
=Q(e1a+e2b)=Q\left(e_{1} a+e_{2} b\right)