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Question

Physics Question on Acceleration

The displacement of a body is given to be proportional to the cube of time elapsed. The magnitude of the acceleration of the body, is

A

constant but not zero

B

increasing with time

C

zero

D

decreasing with time

Answer

increasing with time

Explanation

Solution

Given that displacement of the body,

yt3y \,\propto\,t^{3} ory=kt3\,\,\,\,\,y = kt^{3}

v=dydt=3kt2\therefore\,\,\,\,\,v = \frac{dy}{dt } = 3kt^{2} or a=dvdt=6kt\,\,\,\,a = \frac{dv}{dt} = 6\,kt \propto t

\therefore\,\,\,\,\, The magnitude of the acceleration of the body increases with time.

Therefore, the correct option is (B): increasing with time