Solveeit Logo
Login

Question

Physics Question on Nuclei

The disintegration rate of a certain radioactive sample at any instant is 42504250 disintegrations per minute 1010 minutes later, the rate becomes 22502250 disintegrations per minute The approximate decay constant is : (Take log⁡10188=0274\log _{10} 188=0274 )

A

0.02 min⁡−10.02 \,\min ^{-1}

B

2.7 min⁡−12.7 \,\min ^{-1}

C

0.063 min⁡−10.063 \,\min ^{-1}

D

6.3 min⁡−16.3 \,\min ^{-1}

Answer

0.063 min⁡−10.063 \,\min ^{-1}

Explanation

Solution

The correct option is(C): 0.063 min−1.