Solveeit Logo

Question

Question: The direction cosines of vector \(\mathbf{a} = 3\mathbf{i} + 4\mathbf{j} + 5\mathbf{k}\) in the dire...

The direction cosines of vector a=3i+4j+5k\mathbf{a} = 3\mathbf{i} + 4\mathbf{j} + 5\mathbf{k} in the direction of positive axis of x, is

A

±350\pm \frac{3}{\sqrt{50}}

B

450\frac{4}{\sqrt{50}}

C

350\frac{3}{\sqrt{50}}

D

450- \frac{4}{\sqrt{50}}

Answer

350\frac{3}{\sqrt{50}}

Explanation

Solution

332+42+52=350.\frac{3}{\sqrt{3^{2} + 4^{2} + 5^{2}}} = \frac{3}{\sqrt{50}}.