Question
Question: The direction cosines of the vector \(3\mathbf{i} - 4\mathbf{j} + 5\mathbf{k}\) are...
The direction cosines of the vector 3i−4j+5k are
A
53,5−4,51
B
523,52−4,21
C
23,2−4,21
D
523,524,21
Answer
523,52−4,21
Explanation
Solution
r=3i−4j+5k; ∣r∣=32+(−4)2+52=52
Hence, direction cosines are 523,52−4,525 i.e., 523,52−4,21