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Question: The direction cosine of a line which is perpendicular to both the lines whose direction ratios are \...

The direction cosine of a line which is perpendicular to both the lines whose direction ratios are (1,2,2)(1, - 2, - 2) and (0,2,1)(0,2,1) are
A. (23,13,23)(\dfrac{2}{3}, - \dfrac{1}{3},\dfrac{2}{3})
B. (23,13,23)(\dfrac{2}{3},\dfrac{1}{3},\dfrac{2}{3})
C. (23,13,23)(\dfrac{2}{3},\dfrac{1}{3}, - \dfrac{2}{3})
D. (23,13,23)( - \dfrac{2}{3},\dfrac{1}{3},\dfrac{2}{3})

Explanation

Solution

To find out the direction cosines of a line perpendicular to the lines whose direction ratios are (1,2,2)(1, - 2, - 2) and (0,2,1)(0,2,1), we find the cross product of (1,2,2)(1, - 2, - 2) and (0,2,1)(0,2,1). This will give us the direction ratio of the line required, now we use ll2+m2+n2,ml2+m2+n2,nl2+m2+n2\dfrac{l}{{\sqrt {{l^2} + {m^2} + {n^2}} }},\dfrac{m}{{\sqrt {{l^2} + {m^2} + {n^2}} }},\dfrac{n}{{\sqrt {{l^2} + {m^2} + {n^2}} }} to find the direction cosines of the required line.

Complete step by step answer:

Given direction ratios are (1,2,2)(1, - 2, - 2) and (0,2,1)(0,2,1)
The vectors that can be formed by given direction ratios are ,
i^2j^2k^\widehat i - 2\widehat j - 2\widehat kand 2j^+k^2\widehat j + \widehat k
Now, we need to calculate the vector perpendicular to both the vectors so it can be given as ,

= \left| {\begin{array}{*{20}{c}} {\widehat i}&{\widehat j}&{\widehat k} \\\ 1&{ - 2}&{ - 2} \\\ 0&2&1 \end{array}} \right| \\\ = ( - 2 + 4)\widehat i - (1 - 0)\widehat j + (2 - 0)\widehat k \\\ = 2\widehat i - \widehat j + 2\widehat k \\\

Hence, the direction ratio of vector perpendicular to both the given direction ratios is (2,1,2)(2, - 1,2)
Hence, the direction cosines are
ll2+m2+n2,ml2+m2+n2,nl2+m2+n2\dfrac{l}{{\sqrt {{l^2} + {m^2} + {n^2}} }},\dfrac{m}{{\sqrt {{l^2} + {m^2} + {n^2}} }},\dfrac{n}{{\sqrt {{l^2} + {m^2} + {n^2}} }}

=222+(1)2+22,122+(1)2+22,222+(1)2+22 =23,13,23  = \dfrac{2}{{\sqrt {{2^2} + {{( - 1)}^2} + {2^2}} }},\dfrac{{ - 1}}{{\sqrt {{2^2} + {{( - 1)}^2} + {2^2}} }},\dfrac{2}{{\sqrt {{2^2} + {{( - 1)}^2} + {2^2}} }} \\\ = \dfrac{2}{3},\dfrac{{ - 1}}{3},\dfrac{2}{3} \\\

So, option (a) is our required correct answer.

Note: Any number proportional to the direction cosine is known as the direction ratio of a line. These direction numbers are represented by a, b and c. We can conclude that some of the squares of the direction cosines of a line is 11.
Once, direction ratios are known you can use the formula as per ll2+m2+n2,ml2+m2+n2,nl2+m2+n2\dfrac{l}{{\sqrt {{l^2} + {m^2} + {n^2}} }},\dfrac{m}{{\sqrt {{l^2} + {m^2} + {n^2}} }},\dfrac{n}{{\sqrt {{l^2} + {m^2} + {n^2}} }}to calculate given direction cosines. Calculate without any mistake.