Question
Question: The direction cosine of a line which is perpendicular to both the lines whose direction ratios are \...
The direction cosine of a line which is perpendicular to both the lines whose direction ratios are (1,−2,−2) and (0,2,1) are
A. (32,−31,32)
B. (32,31,32)
C. (32,31,−32)
D. (−32,31,32)
Solution
To find out the direction cosines of a line perpendicular to the lines whose direction ratios are (1,−2,−2) and (0,2,1), we find the cross product of (1,−2,−2) and (0,2,1). This will give us the direction ratio of the line required, now we use l2+m2+n2l,l2+m2+n2m,l2+m2+n2n to find the direction cosines of the required line.
Complete step by step answer:
Given direction ratios are (1,−2,−2) and (0,2,1)
The vectors that can be formed by given direction ratios are ,
i−2j−2kand 2j+k
Now, we need to calculate the vector perpendicular to both the vectors so it can be given as ,
Hence, the direction ratio of vector perpendicular to both the given direction ratios is (2,−1,2)
Hence, the direction cosines are
l2+m2+n2l,l2+m2+n2m,l2+m2+n2n
So, option (a) is our required correct answer.
Note: Any number proportional to the direction cosine is known as the direction ratio of a line. These direction numbers are represented by a, b and c. We can conclude that some of the squares of the direction cosines of a line is 1.
Once, direction ratios are known you can use the formula as per l2+m2+n2l,l2+m2+n2m,l2+m2+n2nto calculate given direction cosines. Calculate without any mistake.