Question

The dipole moment of $H_2S$ is 0.95 D. If the bond angle is $97^\circ$, the S-H bond moment would be (cos 48.5 =0.662)

• A. 0.95 D
• B. 0.662 D
• C. 48.5 D
• D. 0.72 D

Answer 1

Answer: (D)

0.72 D

Answer 2

$\mu_{obs}=\mu_{S-H}Cos97^\circ 2\mu_{S-H}cos48.5$
$0.95=2\mu_{S-H}\times0.662$
$\mu_{S-H}=\frac{0.95}{2\times0.662}=0.72D$