Question

The dipole moment of each molecule of a paramagnetic gas is 1.5 × 10^–23Amp×m². The temperature of gas is 27^oC and the number of molecules per unit volume in it is 2 × 10²⁶m^–3. The maximum possible intensity of magnetization in the gas will be

• A. 3 × 10³Amp/m
• B. 4 × 10^–3Amp/m
• C. 5 × 10⁵Amp/m
• D. 6 × 10^–4Amp/m

Answer 1

Answer: (A)

3 × 10³Amp/m

Answer 2

$\mathrm { I } = \frac { \mathrm { M } } { \mathrm { V } } = \frac { \mu \mathrm { N } } { \mathrm { V } } = \frac { 1.5 \times 10 ^ { - 23 } \times 2 \times 10 ^ { 26 } } { 1 } = 3 \times 10 ^ { 3 } \mathrm { Amp } / \mathrm { m }$