Question
Question: The dipole moment of a given system is: A. \(\sqrt 3 ql\) along a perpendicular bisector of the \(...
The dipole moment of a given system is:
A. 3ql along a perpendicular bisector of the q−q line.
B. 2ql along perpendicular bisector of q−q line.
C. ql2 along perpendicular bisector of q−q line.
D. 0
Solution
Here, we will use the formula of dipole moment to calculate the dipole moment of a given system. Here, a system of charges is taken as an equilateral triangle in which the charges are taken on the three corners of a triangle. Here, the angle at the charge −2q is bisected perpendicularly.
Complete step by step answer:
When there is a separation of charges it will lead to a dipole moment. Also, we can say that the difference in the electronegativity between two chemically bonded charges leads to a dipole moment.
Now, the formula of the dipole moment is given by
μ=Q×r
Here, μ represents the dipole moment, Q represents the charge in the system, and r represents the distance of separation between the two charges.
Here, we can also represent the dipole moment between the charges as P .
Now, in the question, we are given a system of charges, therefore, the dipole moment of the system of charges is given by
P=∑qiri
Now, if we consider a charge −2q as −q−q, therefore, dipoles on both sides are given by ql and −ql .
Also, if we consider a perpendicular bisector of the charge −2q , such that it divides the angle as 30∘−30∘ , hence, the perpendicular component of the dipole is −2qcos30∘ , therefore, the above equation becomes
P=ql−ql+2qlcos30∘
P=2ql×23
P=3ql
Hence, the dipole moment of a given system is 3ql along the perpendicular bisector of the q−q line.
So, the correct answer is “Option A”.
Note:
A bond dipole moment is used to measure the polarity of a chemical bond between two atoms in a molecule. It involves the concept of electric dipole moment that is the measure of the separation of negative and positive charges in a system. The bond dipole moment is different from the dipole moment of the whole molecule.