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Question

Physics Question on Dimensional Analysis

The dimensions of universal gravitational constant are

A

[M1L3T2][{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]

B

[ML2T1][M{{L}^{2}}{{T}^{-1}}]

C

[M2L3T2][{{M}^{-2}}{{L}^{3}}{{T}^{-2}}]

D

[M2L2T1][{{M}^{-2}}{{L}^{2}}{{T}^{-1}}]

Answer

[M1L3T2][{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]

Explanation

Solution

Key Idea : Substitute the dimensions for the quantities involved in an expression written for gravitational constant. According to Newton's law of gravitation, the force of attraction between two masses m1m_{1} and m2m_{2} separated by a distance rr is, F=Gm1m2r2F=\frac{G m_{1} m_{2}}{r^{2}} G=Fr2m1m2 \Rightarrow G=\frac{F r^{2}}{m_{1} m_{2}} Substituting the dimensions for the quantities on the right hand side, we obtain dimensions of G=[MLT2][L2][M2]G=\frac{\left[ MLT ^{-2}\right]\left[ L ^{2}\right]}{\left[ M ^{2}\right]} =[M1L3T2]=\left[ M ^{-1} L ^{3} T ^{-2}\right]