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Question

Question: The dimensions of thermal resistance are...

The dimensions of thermal resistance are

A

M−1L−2T3KM^{- 1}L^{- 2}T^{3}K

B

ML2T−2K−1ML^{2}T^{- 2}K^{- 1}

C

ML2T−3KML^{2}T^{- 3}K

D

ML2T−2K−2ML^{2}T^{- 2}K^{- 2}

Answer

M−1L−2T3KM^{- 1}L^{- 2}T^{3}K

Explanation

Solution

Thermal resistance

=lKA=[LMLT−3K−1×L2]=[M−1L−2T3K]= \frac{l}{KA} = \left\lbrack \frac{L}{MLT^{- 3}K^{- 1} \times L^{2}} \right\rbrack = \lbrack M^{- 1}L^{- 2}T^{3}K\rbrack