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Question

Physics Question on Dimensional Analysis

The dimensions of specific resistance are

A

[ML2T−2A−1][M L^2T^{-2}A^{-1}]

B

[ML3T−3A−2][M L^3T^{-3}A^{-2}]

C

[ML3T−2A−1][M L^3T^{-2}A^{-1}]

D

[ML2T−2A−2][M L^2T^{-2}A^{-2}]

Answer

[ML3T−3A−2][M L^3T^{-3}A^{-2}]

Explanation

Solution

Specific resistance ρ=RAl\rho = \frac{RA}{l} =[ML2T−3A−2][L] = \left[ML^{2} T^{-3} A^{-2}\right]\left[L\right] =[ML3T−3A−2]= \left[ML^{3} T^{-3} A^{-2}\right]