Question

The dimensions of Plank’s constant are the same as that of

• A. Linear impulse
• B. Work
• C. Linear momentum
• D. Angular momentum

Answer 1

Answer: (D)

Angular momentum

Answer 2

Energy of a photon, $E = h\upsilon$Where h is the Planck’s constant and $\upsilon$is the frequency.

$\therefore\lbrack h\rbrack = \frac{\lbrack E\rbrack}{\lbrack\upsilon\rbrack} = \frac{\lbrack ML^{2}T^{- 2}\rbrack}{\lbrack T^{- 1}\rbrack} = \lbrack ML^{- 2}T^{- 1}\rbrack$

Angular momentum = moment of inertia × Angualr velocity

[Angular momentum ] = $\lbrack ML^{2}\rbrack\lbrack T^{- 1}\rbrack = \lbrack ML^{2}T^{- 1}\rbrack$