Solveeit Logo
Login

Question

Question: The dimensions of physical quantity X in the equation Force \(= \frac{X}{\text{Density}}\) is given ...

The dimensions of physical quantity X in the equation Force =XDensity= \frac{X}{\text{Density}} is given by

A

M1L4T−2M^{1}L^{4}T^{- 2}

B

M2L−2T−1M^{2}L^{- 2}T^{- 1}

C

M2L−2T−2M^{2}L^{- 2}T^{- 2}

D

M1L−2T−1M^{1}L^{- 2}T^{- 1}

Answer

M2L−2T−2M^{2}L^{- 2}T^{- 2}

Explanation

Solution

[X] = [Force] × [Density] = [MLT−2]×[ML−3]\lbrack MLT^{- 2}\rbrack \times \lbrack ML^{- 3}\rbrack

= [M2L−2T−2]\left[ M ^ { 2 } L ^ { - 2 } T ^ { - 2 } \right]