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Question

Physics Question on Dimensional Analysis

The dimensions of mobility of charge carriers are

A

M2T2AM^{-2}T^2A

B

M1T2AM^{-1}T^2A

C

M2T3AM^{-2}T^3A

D

M1T3AM^{-1}T^3A

Answer

M1T2AM^{-1}T^2A

Explanation

Solution

Mobility, μ=DriftVelocity(vd)Electricfield(E)\mu=\frac{Drift \,Velocity\left(v_{d}\right)}{Electric \, field \left(E\right)} \therefore \quad [μ]=[vd][E]\left[\mu\right]=\frac{\left[v_{d}\right]}{\left[E\right]} =[M0LT1][MLT3A1]=\frac{\left[M^{0}LT^{-1}\right]}{\left[MLT^{-3} A^{-1}\right]} =[M1T2A]=\left[M^{-1}T^{2}A\right]