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Question

Physics Question on Dimensional Analysis

The dimensions of heat capacity are

A

[ML−2T−2K−1]{[ML^{-2} T^{-2} K^{-1}] }

B

[ML2T−2K−1]{[ML^{2} T^{-2} K^{-1}] }

C

[M−1L2T−2K−1]{[M^{-1}L^{2} T^{-2} K^{-1}] }

D

[MLT−2K]{[MLT^{-2} K] }

Answer

[ML2T−2K−1]{[ML^{2} T^{-2} K^{-1}] }

Explanation

Solution

Heat capacity=Heat energyTemperature{Heat \, capacity = \frac{Heat \, energy}{Temperature}}
            =[ML2T−2][K]=[ML2T−2K−1]\:\:\:\:\:\:\:\:\:\:\:\:= {\frac{[ML^2 T^{-2} ]}{[K]} = [ML^2 T^{-2} K^{-1}]}