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Question: The dimensions of \(\frac{a}{b}\) in the equation P = \(\frac{a–t^{2}}{bx}\)where P is pressure, x i...

The dimensions of ab\frac{a}{b} in the equation P = at2bx\frac{a–t^{2}}{bx}where P is pressure, x is distance and t is time are-

A

[M2LT–3]

B

[MT–2]

C

[ML3T–1]

D

[LT–3]

Answer

MT<sup>2</sup>MT<sup>–2</sup>

Explanation

Solution

[ab]\left\lbrack \frac{a}{b} \right\rbrack = [P][x]

= ML–1T–2L = MT–1