Solveeit Logo

Question

Question: The dimensions of angular momentum, latent heat, and capacitance are, respectively: A. \(M{{L}^{2}...

The dimensions of angular momentum, latent heat, and capacitance are, respectively:
A. ML2T1A2,L2T2,M1L2T2M{{L}^{2}}{{T}^{1}}{{A}^{2}},\,{{L}^{2}}{{T}^{-2}},\,{{M}^{-1}}{{L}^{-2}}{{T}^{2}}
B. MLT2,L2T2,M1L2T4A2ML{{T}^{2}},\,{{L}^{2}}{{T}^{2}},{{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{A}^{2}}
C. ML2T1,L2T2,ML2TA2M{{L}^{2}}{{T}^{-1}},\,{{L}^{2}}{{T}^{-2}},M{{L}^{2}}T{{A}^{2}}
D. ML2T1,L2T2,M1L2T4A2M{{L}^{2}}{{T}^{-1}},\,{{L}^{2}}{{T}^{-2}},{{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{A}^{2}}

Explanation

Solution

- Hint: The physical quantities angular momentum, latent heat, and capacitance are derived quantities. The dimensions can be obtained from the definitions.

Complete step-by-step solution -
Angular momentum: It is the rotational counterpart of linear momentum and defined as,
J=r×p\overrightarrow{J}=\overrightarrow{r}\times \overrightarrow{p}
Here a particle rotates about a point (named the origin) with momentum p\overrightarrow{p} having a distance r\overrightarrow{r} from the origin. The dimension of angular momentum in the product of the dimension of distance and the dimension of linear momentum.
Dimension of distance =L=L
Dimension of linear momentum =MLT1=ML{{T}^{-1}}
Hence, dimension of J=LMLT1=ML2T1J=L\cdot ML{{T}^{-1}}=M{{L}^{2}}{{T}^{-1}}
Latent heat: It is defined as the amount of heat (energy) required to change the state of unit mass of a substance at constant temperature. Hence, its dimension is that of energy per unit mass.
Dimension of energy =ML2T2=M{{L}^{2}}{{T}^{-2}} such that the dimension of latent heat is,
ML2T2M=L2T2\dfrac{M{{L}^{2}}{{T}^{-2}}}{M}={{L}^{2}}{{T}^{-2}}
Capacitance: It is defined as the ratio of charge to electric potential i.e. C=QVC=\dfrac{Q}{V}
Dimension of charge is the product of the dimensions of current and time which isATAT. Dimension of electric potential is the ratio of dimension energy to that of charge. Hence, dimension of capacitance is given by,
(dimension of charge)2(dimension of energy)\dfrac{{{\left( dimension\text{ }of\text{ }charge \right)}^{2}}}{\left( dimension\text{ }of\text{ }energy \right)}
=(AT)2ML2T2=\dfrac{{{(AT)}^{2}}}{M{{L}^{2}}{{T}^{-2}}}
=M1L2T4A2={{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{A}^{2}}
Hence, the correct option is: (D) ML2T1,L2T2,M1L2T4A2M{{L}^{2}}{{T}^{-1}},\,{{L}^{2}}{{T}^{-2}},{{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{A}^{2}}

Note: All the quantities should be expressed in terms of base quantities. The required base quantities in the question are mass, length, time and current. As we know charge is a product of current and time. So the dimensional formula of charge is [AT]\left[ AT \right].