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Question

Physics Question on Dimensional Analysis

The dimensional formula of magnetic flux is

A

[M1L2T1A2]\left[ M ^{1} L ^{2} T ^{-1} A ^{-2}\right]

B

[M1L2T2A1]\left[ M ^{1} L ^{2} T ^{-2} A ^{-1}\right]

C

[M1L2T1A1]\left[ M ^{1} L ^{2} T ^{-1} A ^{-1}\right]

D

[M1L0T2A1]\left[ M ^{1} L ^{0} T ^{-2} A ^{-1}\right]

Answer

[M1L2T2A1]\left[ M ^{1} L ^{2} T ^{-2} A ^{-1}\right]

Explanation

Solution

Magnetic flux, ϕ=B.A=FIλA\phi = B. A =\frac{F}{I\lambda} A
=[M1L+1T2]L2[A.L]=[M1L2T2A1]=\frac{\left[M^{1}L^{+1}T^{-2}\right]L^{2}}{\left[A.L\right]} = \left[M^{1}L^{2}T^{-2}A^{-1}\right]