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Question

Physics Question on Dimensional Analysis

The dimensional formula of electric potential is

A

[ML2T−3A−1][ML^2T^{-3}A^{-1}]

B

[M−1L2T−2A][M^{-1}L^2T^{-2}A]

C

[M−1L2T−2A−1][M^{-1}L^2T^{-2}A^{-1}]

D

[ML2T−2A][ML^2T^{-2}A]

Answer

[ML2T−3A−1][ML^2T^{-3}A^{-1}]

Explanation

Solution

Electric potential,
V=Wq=[ML2T−2][AT]V=\frac{W}{q}=\frac{\left[ML^{2}T^{-2}\right]}{\left[AT\right]}
=[ML2T−3A−1]=\left[ML^{2}T^{-3}A^{-1}\right]