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Question

Physics Question on Dimensional Analysis

The dimensional formula for Youngs modulus is:

A

ML−1T−2ML ^{-1} T ^{-2}

B

M0LT−2M^{0} L T^{-2}

C

MLT−2MLT ^{-2}

D

ML2T−2ML ^{2} T ^{-2}

Answer

ML−1T−2ML ^{-1} T ^{-2}

Explanation

Solution

The formula for the Young's modulus
Y= stress  strain Y =\frac{\text { stress }}{\text { strain }}
Dimensions of Y=ML−1 T−2M0 L0 T0Y =\frac{ ML ^{-1} \,T ^{-2}}{ M ^{0} \,L ^{0}\, T ^{0}}
=ML−1 T−2= ML ^{-1}\, T ^{-2}