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Question: The dimensional formula for Planck's constant \((h)\) is...

The dimensional formula for Planck's constant (h)(h) is

A

ML−2T−3ML^{- 2}T^{- 3}

B

ML2T−2ML^{2}T^{- 2}

C

ML2T−1ML^{2}T^{- 1}

D

ML−2T−2ML^{- 2}T^{- 2}

Answer

ML2T−1ML^{2}T^{- 1}

Explanation

Solution

E=hv⇒[ML2T−2]=[h][T−1]⇒[h]=[ML2T−1]E = hv \Rightarrow \lbrack ML^{2}T^{- 2}\rbrack = \lbrack h\rbrack\lbrack T^{- 1}\rbrack \Rightarrow \lbrack h\rbrack = \lbrack ML^{2}T^{- 1}\rbrack