Question

The dimensional formula for Planck’s constant and angular momentum are,
A. $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-2}}} \right]\text{ and }\left[ \text{ML}{{\text{T}}^{\text{-1}}} \right]$
B. $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]\text{ and }\left[ C. \text{M}{{\text{L}}^{2}}{{\text{T}}^{\text{-1}}} \right]$
C. $\left[ \text{M}{{\text{L}}^{3}}{{\text{T}}^{1}} \right]\text{ and }\left[ \text{M}{{\text{L}}^{2}}{{\text{T}}^{\text{-2}}} \right]$
D. $\left[ \text{ML}{{\text{T}}^{\text{-1}}} \right]\text{ and }\left[ \text{ML}{{\text{T}}^{\text{-2}}} \right]$

Answer 1

Hint: Think about how the Planck’s constant is related to energy and frequency and how angular momentum is related to moment of inertia and angular velocity.

Complete step by step answer:
The energy radiated by an electromagnetic wave for example light at a particular frequency $\text{( }\\!\\!\nu\\!\\!\text{ )}$ is given by $\text{E}=\text{h }\\!\\!\nu\\!\\!\text{ }$, so the Planck constant can be expressed as the ratio of energy and frequency, $\text{h}=\text{E/ }\\!\\!\nu\\!\\!\text{ }$. The dimensional formula associated with energy is $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-2}}} \right]$ and the dimensional formula for frequency is $\left[ {{\text{T}}^{\text{-1}}} \right]$.
So the dimensional formula for Planck’s constant can be derived from these,
$h=\dfrac{\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-2}}} \right]}{\left[ {{\text{T}}^{\text{-1}}} \right]}=\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]$
So the dimensional formula for Planck’s constant is $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]$.
The angular momentum of a body whose moment of inertia is I and angular velocity $\text{ }\\!\\!\omega\\!\\!\text{ }$ is given by the formula $\text{L}=\text{I }\\!\\!\omega\\!\\!\text{ }$, The dimensional formula for moment of inertia is given by $\left[ \text{M}{{\text{L}}^{\text{2}}} \right]$ and the dimensional formula for angular velocity is $\left[ {{\text{T}}^{\text{-1}}} \right]$ so the dimensional formula for angular momentum is the product of these two dimensional formulas,
$\text{L}=\left[ \text{M}{{\text{L}}^{\text{2}}} \right]\left[ {{\text{T}}^{\text{-1}}} \right]=\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]$
So the dimensional formula for angular momentum is $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]$.
So considering the dimensional formulas we got for Planck’s constant and angular momentum, the answer to our question will be option (B)- $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]$ and $\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-1}}} \right]$.
As you can see that the dimensional formula for both the quantities are same.

Note: The angular momentum can also be expressed as the product of a body of mass m, its linear velocity and the distance r from the axis. $\text{L}=\text{mvr}$.
$\left[ \text{M}{{\text{L}}^{\text{2}}}{{\text{T}}^{\text{-2}}} \right]$ is the dimensional formula for Energy.
$\left[ \text{ML}{{\text{T}}^{\text{-2}}} \right]$ is the dimensional formula for force.
$\left[ \text{ML}{{\text{T}}^{\text{-1}}} \right]$ is the dimensional formula for momentum.