Question
Physics Question on Dimensional Analysis
The dimensional formula for permittivity of free space ((ϵ)0) in the equation F=4πϵ01r2q1q2 , where symbols have their usual meaning, is
A
[M1L3A−2T−4]
B
[M−1L−3T4A2]
C
[M−1L−3A−2T−4]
D
[M1L3T2A−4]
Answer
[M−1L−3T4A2]
Explanation
Solution
As, F=4πϵ01r2q1q2 ⇒ϵ0=4πFr2q1q2 =[L2][MLT−2][TA]2 =[M−1L−3T4A2]